Artists struggle with hands just as much as AIPage 11, driver's hands are way too small, no?
Mate, they are just math problems using real world stuff as ideas, having pure math problems is boring.This chapter is proof that you cannot convincely portray a character smarter than you actually are, and that the author is definitely not the sharpest bulb in the drawer: both of the riddles makes absolutely no sense from the logical point of view, but even if we assume they did, and that the "reasoning" presented is actually correct, the calculations and the final results are still wrong.
First of all, the bank one: in the real world, you deposit some money, and after a fixed amount of time you get your money back, plus the interest (minus taxes). Under this premises, after a single administrative cicle you get your initial investment (300), plus interest (50), totaling 350.
In the Bizzarro universe, instead, banks also pay you interests on the interests you have yet to mature. In this case the total is given by your original investment (300) plus the interest (300*1/6) plus the interest on the interest (300*1/6*1/6) plus the interest on the interest on the interest (300*1/6*1/6*1/6) and so on and so forth ad infinitum; if you collect the initial investment from all the term, you are left with the following summation 1 + 1/6 + (1/6)^2 + (1/6)^3 + (1/6)^4 +...
This is a geometric series, and its value is 6/5: multiplied by 300 you get 360. This is the "correct" answer, assuming the Bizzarro logic. Notice how it wasn't between the available answers.
The moon one is even worse:
neglecting the fact the moon is neither black nor white, but dark grey, it is always half in the light and half in the darkness (except for eclipses, when it's all in the darkness). If you land on the side in the light you can be 100% sure the other side is in the darkness (unless proxima centauri just went supernova, but then you would have a more pressing concern than this dumb riddle).
In the Bizzarro universe, apparently the moon is a giant ping pong ball, painted by magic rabbits: at this point why should we be limited to the three cases presented, and not maybe 1/4 white, 1/4 black, and the hidden half green with magenta pois? How do you justify moon phases, in the case of full white or full black moon? How do you even define a "side" of a sphere?
But fine, let's assume the moon has two distinct faces, that we will call A and B, and these two faces can be either white or black: the three cases presented (full black, full white, half and half) are actually four in disguise: A black B black, A black B white, A white B black, A white B white. Let's land on a random side, and we see it is white: we can discard the two cases where that face was black and we are left with two equally probable cases were the moon is either full white or half/half. The same also applied if we landed on the other face, so in the end the right answer is 1/2. At least this time the correct answer was one of the two available...
It seems you are missing my points:Mate, they are just math problems using real world stuff as ideas, having pure math problems is boring.
Ya wanna also consider inflation? What would happen if an economic crisis happened? Or if, after getting the money, you trip and drop them down an open drain?
Same thing for the moon thing, but also they did not made the moon green cause that was not part of the problem, if they wanted and was needed then making the moon green would've made sense, even if unrealistic in the real world.
Last thing is you're correct with the moon answer being 1/2 instead of 2/3: question basically asks chances of you being on a full white moon, so, since there are only 3 phases (black&white and white&black are the same since initial position is random), and it's clear you're not on the full black moon, then you only have 2 choices between full white and half&half => 1/2 chances.
Another way to see that is using the 4 phases like you said and not considering b&w and w&b the same, and after discarding the full black moon, we can say there's 2/4 chances for it being a full white moon (we could be on the back of the full moon, front of the full moon, back of the black&white moom, front of the white&black moon), still resulting in 1/2.
Guess author got confused with the problem, where you can, somehow, reach the white side of the half&half moon, since if so, then it would've been 2/3.
It's 359 because it rounds down. I'm guessing there's no lower denomination than 1 gold coin, so anything after 1/6^3 is just conisdered 0 (300*1/6^4 = 0.23 ≈ 0), rather than summing them all up then rounding. It's true that interest doesn't actually work like that (each interest cycle wouldn't add interest on the interest, it would add interest on top of the total, so it wouldn't be a geometric series) , but it is what it is.This chapter is proof that you cannot convincely portray a character smarter than you actually are, and that the author is definitely not the sharpest bulb in the drawer: both of the riddles makes absolutely no sense from the logical point of view, but even if we assume they did, and that the "reasoning" presented is actually correct, the calculations and the final results are still wrong.
First of all, the bank one: in the real world, you deposit some money, and after a fixed amount of time you get your money back, plus the interest (minus taxes). Under this premises, after a single administrative cicle you get your initial investment (300), plus interest (50), totaling 350.
In the Bizzarro universe, instead, banks also pay you interests on the interests you have yet to mature. In this case the total is given by your original investment (300) plus the interest (300*1/6) plus the interest on the interest (300*1/6*1/6) plus the interest on the interest on the interest (300*1/6*1/6*1/6) and so on and so forth ad infinitum; if you collect the initial investment from all the term, you are left with the following summation 1 + 1/6 + (1/6)^2 + (1/6)^3 + (1/6)^4 +...
This is a geometric series, and its value is 6/5: multiplied by 300 you get 360. This is the "correct" answer, assuming the Bizzarro logic. Notice how it wasn't between the available answers.
The moon one is even worse:
neglecting the fact the moon is neither black nor white, but dark grey, it is always half in the light and half in the darkness (except for eclipses, when it's all in the darkness). If you land on the side in the light you can be 100% sure the other side is in the darkness (unless proxima centauri just went supernova, but then you would have a more pressing concern than this dumb riddle).
In the Bizzarro universe, apparently the moon is a giant ping pong ball, painted by magic rabbits: at this point why should we be limited to the three cases presented, and not maybe 1/4 white, 1/4 black, and the hidden half green with magenta pois? How do you justify moon phases, in the case of full white or full black moon? How do you even define a "side" of a sphere?
But fine, let's assume the moon has two distinct faces, that we will call A and B, and these two faces can be either white or black: the three cases presented (full black, full white, half and half) are actually four in disguise: A black B black, A black B white, A white B black, A white B white. Let's land on a random side, and we see it is white: we can discard the two cases where that face was black and we are left with two equally probable cases were the moon is either full white or half/half. The same also applied if we landed on the other face, so in the end the right answer is 1/2. At least this time the correct answer was one of the two available...