I graphed the equation. Do the ones he has written down, β
π¦=β(1β(π₯β1)^2 )β and β
π¦=β(0.01β(π₯β1)^2 )+1β. Then change both x's to negative β
π¦=β(1β(βπ₯β1)^2 )β and β
π¦=β(0.01β(βπ₯β1)^2 )+1β for the full deal.