Girl Meets Rock! - Ch. 79

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Rin's spitefulness in addition to all her other "fine" qualities is not gonna do any good neither for the LMC nor for the band, especially if she's gonna deliberately pick a fight because of her wounded pride
 
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Sorry Momo, didn't liked your clothes (and that thing bellow the jacket).

But... WHY?!
Suddenly a "fansevice" of one of the girls bathing out of nowhere?
 
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Rin's spitefulness in addition to all her other "fine" qualities is not gonna do any good neither for the LMC nor for the band, especially if she's gonna deliberately pick a fight because of her wounded pride

Unfortunately among all this huge cast Rin is the one character that isn't a good person.
Starting to dislike her.

But at least seems like we'll have a new cool character soon.

Screenshot-20250906-163703.jpg
 
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Ok, but that shower scene was so random.
>What are you reading? Uh, just some title about girls making music - hold up :lewd:

I was thinking to myself "what are the odds 6 out of 7 people make the same choice on rock, paper, scissors", when I remembered I could just calculate it: It's ~0,64% for anyone else interested :thumbsup:

Yuki seemed to feel obligated to leave a spot for Protocol, I'd like to see a tiny arc focusing on her after the band w/ Momo split up / see her gain more confidence. So far, she's kind of the sad supporting side char :glee:
 
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I was thinking to myself "what are the odds 6 out of 7 people make the same choice on rock, paper, scissors", when I remembered I could just calculate it: It's ~0,64% for anyone else interested :thumbsup:
Are you sure about your math? My quick and admittedly improvisational solution is to take 1/3 (three choices, right) and take that to the power of five (you need five people to agree with the first one to get six, what n7 does is irrelevant). That gives me 0.411522633%. Maybe I'm missing something. Ofc all of that's only if you take phychology out of it and assume every choice is equally as common (it isn't).
 
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Are you sure about your math? My quick and admittedly improvisational solution is to take 1/3 (three choices, right) and take that to the power of five (you need five people to agree with the first one to get six, what n7 does is irrelevant). That gives me 0.411522633%. Maybe I'm missing something. Ofc all of that's only if you take phychology out of it and assume every choice is equally as common (it isn't).
If anything, I'd understand that argument if you said (1/3)^6. But that'd be the odds to get 6 times the same choice in a row, while the order doesn't matter for us here (or at least that's how I went about this).
Which is why I used a binomial distribution with p=1/3, n=7 and k=6. That should get us the odds for 6 out of 7 random events having the desired outcome with a probability of 1/3.
 
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If anything, I'd understand that argument if you said (1/3)^6.
It's not ^6 because the first choice doesn't matter, only the 5 after that that have to follow its lead.
But that'd be the odds to get 6 times the same choice in a row, while the order doesn't matter for us here (or at least that's how I went about this).
Which is why I used a binomial distribution with p=1/3, n=7 and k=6. That should get us the odds for 6 out of 7 random events having the desired outcome with a probability of 1/3.
Fair enough, tnx
 

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