She has no control over her power at all, just unconsciously seducing every girl she meets.
Roodypatooti Dex-chan lover Joined Feb 17, 2020 Messages 866 Sep 19, 2024 #21 She has no control over her power at all, just unconsciously seducing every girl she meets.
Evangelear Dex-chan lover Joined Jan 12, 2023 Messages 420 Sep 19, 2024 #22 Nautical said: So is Suzuo also Umashi? Click to expand... No, Suzuo is (was) also ZUO. Umashi is a separate person who wrote a fanfic that ZUO/Suzuo then drew an adaptation of. Basically, Umashi: writer; Suzuo/ZUO: artist.
Nautical said: So is Suzuo also Umashi? Click to expand... No, Suzuo is (was) also ZUO. Umashi is a separate person who wrote a fanfic that ZUO/Suzuo then drew an adaptation of. Basically, Umashi: writer; Suzuo/ZUO: artist.
Nuwanda1313 Aggregator gang Joined Sep 15, 2023 Messages 48 Sep 19, 2024 #23 rageeeeee said: uspoken rizz Click to expand... At this point this is not unspoken Rizz it's legendary Rizz, maybe even Mythical Rizz
rageeeeee said: uspoken rizz Click to expand... At this point this is not unspoken Rizz it's legendary Rizz, maybe even Mythical Rizz
Nuwanda1313 Aggregator gang Joined Sep 15, 2023 Messages 48 Sep 19, 2024 #24 NO NO NO, THIS IS TOO MUCH!!! THE 3 OF THEM ARE SO PRECIOUS, I DON'T EVEN KNOW WHO TO ROOT FOR!!! the narrative seems to be pointing towards a single winner in the endgame, but now I want the harem ending!
NO NO NO, THIS IS TOO MUCH!!! THE 3 OF THEM ARE SO PRECIOUS, I DON'T EVEN KNOW WHO TO ROOT FOR!!! the narrative seems to be pointing towards a single winner in the endgame, but now I want the harem ending!
R recklessribbon Dex-chan lover Joined Jan 13, 2020 Messages 977 Sep 21, 2024 #25 Thanks for the translation!
sebaasdf Dex-chan lover Joined Mar 24, 2020 Messages 384 Sep 22, 2024 #26 These girls are totally broken without her, they will probably die if this doesn't end as a harem
T tondave12345 Aggregator gang Joined Dec 15, 2023 Messages 94 Wednesday at 1:09 PM #28 Born with powerful rizz. Is it possible to learn such power?