Group Leader
- Joined
- Nov 24, 2024
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I salute You , the one who reads My post herein written , with Mine Endless gratitude wishing Luck upon You of a Bright future ; ergo , let This Humble servant nay bubble about entrance but the matter You have came to read or more correctly : what have I meant by the Ominous term " Bird bridge " - pray not ; I will tell , however You will need to track math after what's hereunto written : while I was reading a Romance manga to spend My time , Such Self-talk has occured for the Female Human character : " I’M SO STUPID! I MEAN, THOSE TWO ARE THE WEAVER GIRL AND COWHERD!! " - alas , being the Unhinged & Lazy reader I am being , I skipped the TLN part and left baffled because I didn't know what , or rather - who , " WEAVER GIRL AND COWHERD " were ; for those who are curious the TLN is " Notes: The Cowherd and the Weaver Girl is a Chinese folktale about two literally star-crossed lovers who meet and instantly fall in love, but cannot be together because they inhabit different heavenly realms. In the Japanese version, the Weaver Girl is the daughter of the Sky King, who separates the two because their love interferes with their duties. However, she and the Cowherd are allowed to meet once a year on the 7th day of the 7th lunar month [ using a " Bird bridge " made out of magpies ] , which the Japanese celebrate as the Tanabata festival. " - causing Me to search the story , leading to This math henceforth written.
ARITHMETICPART
( I ) We need axioms as following ;
( 1 ) Magpies :
( A ) Length of a magpie : ~45 cm ( 0.45 meters ) ,
( B ) Wingspan : ~60 cm ( 0.6 meters ) ,
( V ) Thickness / Height ( chest to back ) : ~10 cm ( 0.1 meters ) ,
( G ) Volume per bird ( approx. ) : ~0.001 cubic meters ,
( D ) Weight per bird : 200 GR ,
( 2 ) Bridge :
( A ) Length :
( a ) 16 light-years between Vega & Altair = 151 376 000 000 000 km ,
( b ) Add star girth : + 3 000 000 km from Vega & + 2 400 000 km from Altair ; because , We will put the bridge under Them ,
( c ) Final Bridge Length : 151 381 400 000 000 km ,
( B ) Width : 3 000 000 km ,
( V ) Layer amount : 2 624 ; taken from 600 BCE until 2025 ,
( II ) Now let Us construct 1 layer ;
( 1 ) Magpies along the length :
( A ) Bridge length is from (I/(2.A.c)) ,
( B ) Magpie body length is 0.00045 km (I/(1.A)) ,
( C ) Magpies lengthwise = (I/(2.A.c)) ÷ (II/(1.B)) ≈ 3.3640311 × 10¹⁷ magpies ,
( 2 ) Magpies across the width :
( A ) Magpie wingspan is 0.0006 km from (I/(1.B)) ,
( B ) Magpies widthwise = (I/(2.B)) ÷ (II/(2.A)) = 5.0 × 10⁹ magpies ,
( 3 ) Therefore ; Total magpies is as follows :
L × W × h = ( 3.3640311 × 10¹⁷ ) × ( 5.0 × 10⁹ ) × 1 ≈ 1.6820156 × 10²⁷ , therefore ;
Let : M = 1.6820156 × 10²⁷ , Number of magpies in one layer (II/(3)) Vₘ = 0.001 m³ , Volume per magpie (I/(1.G))
Then : V₁ = M × Vₘ = ( 1.6820156 × 10²⁷ ) × 0.001 = 1.6820156 × 10²⁴ m³ = 1.6820156 × 10¹⁵ km³
Let : M = 1.6820156 × 10²⁷ , Number of magpies in one layer (II/(3)) Vₘ = 0.001 m³ , Volume per magpie (I/(1.G))
Then : V₁ = M × Vₘ = ( 1.6820156 × 10²⁷ ) × 0.001 = 1.6820156 × 10²⁴ m³ = 1.6820156 × 10¹⁵ km³
( III ) Now let Us construct All layers , given orihime & hikoboshi re-build the bridge annually - the year of Our lord twenty twenty-five included ;
Let : L = (I/(2.V)) , h = (I/(1.V)) , V₁ = Result of (II/(3)) , M₁ = 1.6820156 × 10²⁷
Then : H = L × h = 2 624 × 0.1 = 262.4 m
Therefore ;
= Vₜ = L × V₁ = 2624 × ( 1.6820156 × 10²⁴ ) = 4.4136089 × 10²⁷ m³ = 4.4136089 × 10¹⁸ km³
= Mₜ = L × M₁ = 2 624 × ( 1.6820156 × 10²⁷ ) = 4.4136089 × 10³⁰ m³
Then : H = L × h = 2 624 × 0.1 = 262.4 m
Therefore ;
= Vₜ = L × V₁ = 2624 × ( 1.6820156 × 10²⁴ ) = 4.4136089 × 10²⁷ m³ = 4.4136089 × 10¹⁸ km³
= Mₜ = L × M₁ = 2 624 × ( 1.6820156 × 10²⁷ ) = 4.4136089 × 10³⁰ m³
( IV ) Now let Us explain the logistics of This operation ; They meet once a year , so We take the Lunar calendar and exclude the One Single day They meet :
Let : Lunar year ≈ 354 days
Exclude Tanabata → Remaining means D = 354 − 1 = 353
t = D × 86 400 = 30 499 200 seconds
Let : Sm be " Sewing times " , S be " Sewings "
Then : S = M × Sm = ( 1.6820156 × 10²⁷ ) × 4 = 6.7280624 × 10²⁷
Therefore ; S/t ≈ 2.206×10²⁰ & M/t ≈ 5.515 × 10¹⁹
Exclude Tanabata → Remaining means D = 354 − 1 = 353
t = D × 86 400 = 30 499 200 seconds
Let : Sm be " Sewing times " , S be " Sewings "
Then : S = M × Sm = ( 1.6820156 × 10²⁷ ) × 4 = 6.7280624 × 10²⁷
Therefore ; S/t ≈ 2.206×10²⁰ & M/t ≈ 5.515 × 10¹⁹