No no, thats not how gacha works. No matter how many times you try, the percentage won't change.The chance of something within 181 days was about 83.8%.
They are talking about the probability over 181 attempts rather than each individual attempt, but I think their math isn't exactly right. The odds of failing 181 times in a row is 16.22%, and 1 - .1622 would be 83.78%, but this isn't the chance of the next attempt being a success. That only works with the base probability.No no, thats not how gacha works. No matter how many times you try, the percentage won't change.
Unless the number of slime is already decided like, out of 100 slime's there only 1 win slime, then the chance will go up on each fail.
After seeing countless of this kind of manga, just give it few/some more chaptersActually not a shitty cliche of a love interest.
I saidNo no, thats not how gacha works. No matter how many times you try, the percentage won't change.
Unless the number of slime is already decided like, out of 100 slime's there only 1 win slime, then the chance will go up on each fail.
Not “on the 181st day”.within 181 days
It's right to one hundredth of a percent. (Few people want more precision than that.)I think their math isn't exactly right.
At this point, you confuse one success with exactly one success, whereas I didn't refer to one as such at all. I wrote ofThe probability of 1 success over 181 attempts
The main character has no reason to prefer exactly one drop. That would be like asking “Is there a doctor in the house?” and hoping that there weren't two.something within 181 days
welp, conditional probability is hardThey are talking about the probability over 181 attempts rather than each individual attempt, but I think their math isn't exactly right. The odds of failing 181 times in a row is 16.22%, and 1 - .1622 would be 83.78%, but this isn't the chance of the next attempt being a success. That only works with the base probability.
The probability of 1 success over 181 attempts would be calculated with (n!/(n-x)!x!)(p^x)(q^n-x) where n is the number of attempts, x is the number of successes, p is the chance of success and q is the chance of failure.
This would be 181•.01•.1638=.2965, or 29.65%
This is still only the chance of 1 success in 181. It doesn't tell us the chance that the 181st one is a success, just that there has been 1 success until this point.
The chance that specifically the 181st is a success would be 1% like you said.
Apparently the English language is harder, because he refuted something that I didn't say, as did the other guy.welp, conditional probability is hard
Or maybe she's honest and really doesn't have any romantic interest in the MCYeah ... that's the childhood friend's fault for getting mad if MC actually gets a love interest other than her. Should have been honest. I wouldn't blame him for being mad.