Sousaku Imouto - Ch. 9
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wouldnt want it any other way.
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id not, i know my luck
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Any connection to the diary of concerned imoutos?
Thaaaat's what I remembered. They are "Diary of Concerned Imoutos", jokes of the credits page of Arousing Imouto Scanlations (not sure if still active) detailing the inner thoughts of a young sister in a incest-happpy environment. Here, take a look:
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People said elementary schooler, and middle schooler count as underaged too. Pretty sure high schooler count too, but they often get a pass as a "close enough" in that standard it seems.
Personally don't really care that much though.
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Stop hanging around in /v/ translator, mental health is rare breed these times
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ah thanks bro
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Well boys its official, we goin' to get h*ntai of this at last.
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That's better than my usual Gacha game luck lol.
Tried that when we were kids in the past, ended up being the guy who tends my sister's long hair every bath time which was a pain to do as a kid lol.
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HOLY SHIT THAT 98.75% COPYPASTA IS MINE
I wrote it for the Coffin of Andy and Leyley threads on /v/
It's a very sweet game that recently came out, about an hour long, with psycho goth sibling incest. If you liked Sousaku Imouto then definitely go play that game
I wrote it for the Coffin of Andy and Leyley threads on /v/
It's a very sweet game that recently came out, about an hour long, with psycho goth sibling incest. If you liked Sousaku Imouto then definitely go play that game
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omg what a small world
Anyway if you want the actual mathematical breakdown for the 98.75% figure, I also supplied that on /v/ as follows:
The reason inbreeding is risky is because there's a possibility you both carry a recessive, deleterious mutation from your ancestors, and therefore a possibility the child will receive both of these alleles and express the trait.
Let's assume the mother carries an allele that is not only recessive, but deleterious. Since it's recessive, you need two of them to actually express the trait, which is why inbreeding can cause these traits to appear (since the alleles are unique to the bloodline).
Anyway, the father is not related to the mother, so does not carry these harmful traits. We will label the retarded allele "R", and any non-retarded allele "N". The mother has one R and one N, and the father has two N's.
The possible combination of alleles from the mother and father will be RN, RN, NN, and NN.
Half of these combinations have an R, which is a 50% probability of a child carrying the allele—but since we are looking at TWO siblings, you times that by another 50% to get the probability of two children in a row carrying the retarded allele, which is 25%.
Of course, that's just carrying, since the mutation doesn't exist in the father's bloodline.
If Andrew and Ashley indeed both carry the recessive allele, then these are the possible outcomes for one child: RN, RR, NR, NN.
Only one out of four combinations has two retarded alleles, which is 25%. So, we times that 25% by the 25% likelihood that Andrew and Ashley even carry the retarded allele to get a 6.25% chance that their first child will be retarded.
And that's assuming the mutation is even harmful. Mutation is random, so the vast majority are neither harmful nor beneficial. So really, that 6.25% figure is the likelihood of the child inheriting a recessive allele regardless of whether it is harmful. The absolute highest estimate by science is that 20% of mutations are harmful, so we times that 6.25% by 20% to get the worst-case scenario of a mere 1.25%—the likelihood of imouto nakadashi resulting in retarded babies.
Anyway if you want the actual mathematical breakdown for the 98.75% figure, I also supplied that on /v/ as follows:
The reason inbreeding is risky is because there's a possibility you both carry a recessive, deleterious mutation from your ancestors, and therefore a possibility the child will receive both of these alleles and express the trait.
Let's assume the mother carries an allele that is not only recessive, but deleterious. Since it's recessive, you need two of them to actually express the trait, which is why inbreeding can cause these traits to appear (since the alleles are unique to the bloodline).
Anyway, the father is not related to the mother, so does not carry these harmful traits. We will label the retarded allele "R", and any non-retarded allele "N". The mother has one R and one N, and the father has two N's.
The possible combination of alleles from the mother and father will be RN, RN, NN, and NN.
Half of these combinations have an R, which is a 50% probability of a child carrying the allele—but since we are looking at TWO siblings, you times that by another 50% to get the probability of two children in a row carrying the retarded allele, which is 25%.
Of course, that's just carrying, since the mutation doesn't exist in the father's bloodline.
If Andrew and Ashley indeed both carry the recessive allele, then these are the possible outcomes for one child: RN, RR, NR, NN.
Only one out of four combinations has two retarded alleles, which is 25%. So, we times that 25% by the 25% likelihood that Andrew and Ashley even carry the retarded allele to get a 6.25% chance that their first child will be retarded.
And that's assuming the mutation is even harmful. Mutation is random, so the vast majority are neither harmful nor beneficial. So really, that 6.25% figure is the likelihood of the child inheriting a recessive allele regardless of whether it is harmful. The absolute highest estimate by science is that 20% of mutations are harmful, so we times that 6.25% by 20% to get the worst-case scenario of a mere 1.25%—the likelihood of imouto nakadashi resulting in retarded babies.
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Oh! and I almost forgot, the explanation for the 75% figure, also from /v/:
Either parent gives you a random 50% of their genes, and as a result you will share 50% of your genes with your siblings.
This means if you impregnate your sister, there is a 50% chance of any given gene being an identical pair.
So, you share 50% of your genes with your sister, thus you times this by the 50% chance of an identical pair, which equals 25%. That 25% is the expected genes your sister will provide the child which she also shares with you. Add this to the 50% of your genes that you yourself provide, and you are expected to be a 75% genetic match with your child if you nakadashi your imouto.
Either parent gives you a random 50% of their genes, and as a result you will share 50% of your genes with your siblings.
This means if you impregnate your sister, there is a 50% chance of any given gene being an identical pair.
So, you share 50% of your genes with your sister, thus you times this by the 50% chance of an identical pair, which equals 25%. That 25% is the expected genes your sister will provide the child which she also shares with you. Add this to the 50% of your genes that you yourself provide, and you are expected to be a 75% genetic match with your child if you nakadashi your imouto.
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After a little searching I found this and its reply https://desuarchive.org/a/thread/250780386/#250899271
And you're missing a few variables like having multiple dodgy genes
In research labs they solve this all the time to create standardised research animals like mice by breeding brother and sister together for 50 generations, they just run large numbers of concurrent pairs and pick the better pair from each litter to breed the next generation, those without clean genes just get purged out. You can get some very weird effects from these studies.
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A few?!? Try 99% of them.
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The translator is fucking unhinged lmao.
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