@Xystus
So, I can sort of explain the Monty Hall problem better than the manga did.
1. There are two bitter gumballs and one sweet gumball. Chita asks Seto to pick one, and stops him before he eats it. She then reveals that one of the other two are bitter, and asks him if he wants to pick a different one.
2. Seto has a 1/3 chance of picking the sweet gumball initially, and a 2/3 chance of picking a bitter gumball.
3. If Seto picks the sweet gumball initially, Chita must reveal where one of the bitter gumballs is. Both of the other gumballs are bitter in this case, so she picks randomly.
4. However, if Seto picks a bitter gumball initially, Chita will reveal where the one remaining bitter gumball is.
Using this logic, revealing the location of one of the two bitter gumballs doesn't eliminate it from the game. Instead, Seto already had a 2/3 chance of initially choosing a bitter gumball. Since the other remaining gumball will be revealed to Seto 2/3 times each time he plays the same game, he is more likely to get the sweet gumball if he switches from his initial choice.
I hope that makes sense. 🤔